t^2=109.39/5

Solution for t^2=109.39/5 equation:

t^2=109.39/5

We move all terms to the left:

t^2-(109.39/5)=0

We add all the numbers together, and all the variables

t^2-(+109.39/5)=0

We get rid of parentheses

t^2-109.39/5=0

We multiply all the terms by the denominator


t^2*5-109.39=0

Wy multiply elements

5t^2-109.39=0

a = 5; b = 0; c = -109.39;
Δ = b2-4ac
Δ = 02-4·5·(-109.39)
Δ = 2187.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2187.8}}{2*5}=\frac{0-\sqrt{2187.8}}{10}
=-\frac{\sqrt{}}{10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2187.8}}{2*5}=\frac{0+\sqrt{2187.8}}{10}
=\frac{\sqrt{}}{10}
$